Trebetheric<p>Amikoj who like maths: I'm trying to find the name of a math operation. Please help if interested!</p><p>It's similar to "choose"<br> 4 choose 2 = 6<br>because there are six ways to choose 2 things from four. Similarly, <br> 5 choose 2 = 10 <br>There are ten ways. </p><p>But what if the five things are in a circle and we don't (re)count as new instances the ones that look the same when rotated? <br>5 ___ 2 = 2 (I'm pretty sure) <br>The 2 items can be either 1 and 4 apart or 2 and 3 apart.<br>I'm looking for the underlined operation. </p><p>5 ___ 3 = 2 <br>If the items are ABCDE, where E is connected to A, the two configurations are 1. ABC (three together), 2. ABD (two, skip one, one). In the case of 5 items ACD is equivalent to 2 because CDA is two, skip one, one.For my purposes they must be equivalent by rotation only, not by flipping.</p><p>6 ___ 3 = 4<br>ABCDEF has ABC, ABD, ABE, and ACE. All others should be equivalent if I counted correctly. </p><p>What is this operation called? 🙏</p><p><a href="https://mastodonapp.uk/tags/maths" class="mention hashtag" rel="nofollow noopener noreferrer" target="_blank">#<span>maths</span></a> <a href="https://mastodonapp.uk/tags/math" class="mention hashtag" rel="nofollow noopener noreferrer" target="_blank">#<span>math</span></a> <a href="https://mastodonapp.uk/tags/discretemath" class="mention hashtag" rel="nofollow noopener noreferrer" target="_blank">#<span>discretemath</span></a> <a href="https://mastodonapp.uk/tags/permutation" class="mention hashtag" rel="nofollow noopener noreferrer" target="_blank">#<span>permutation</span></a></p>